The stable matching problem deals with creating a self-reinforcing selection process. There are two groups, and all the members of each group has a preference profile that lists ranks all members of the other group in order of who that member would like to be matched with. The solution should be self-reinforcing, meaning that members not paired together have no desire to change their matching after the algorithm finishes. The Gale-Shapley algorithm solves the problem as follows for two groups A and B, where all members are initially unmatched:

While there is still a free member in A
Choose a member "a" in A
Let "b" be highest ranked member of B in "a"'s preference list that a has not already tried to match with
If "b" is not already matched with another member of A, then "b" matches with "a"
Else if "b" is already matched
     If "a" is higher on "b"'s preference list than "b"'s current match, then a matches with "b" and "b"'s previous match becomes unmatched
     Else "a" remains free

In terms of readability I would rank this section a 7/10.