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| courses:cs211:winter2018:journals:cohene:home:chapter4 [2018/03/04 22:42] – [4.5: The Minimum Spanning Problem] cohene | courses:cs211:winter2018:journals:cohene:home:chapter4 [2018/03/12 23:28] (current) – Added Section 4.8 cohene | ||
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| This section applies an exchange argument to solve the Minimum Spanning Problem. The minimum spanning problem occurs when there is a set of locations that can be represented through nodes and we want to create a network on top of those locations. The network should be connected, having a path between each location, with the goal of creating the " | This section applies an exchange argument to solve the Minimum Spanning Problem. The minimum spanning problem occurs when there is a set of locations that can be represented through nodes and we want to create a network on top of those locations. The network should be connected, having a path between each location, with the goal of creating the " | ||
| - | We know that the minimum-cost solution to this problem can be turned into a tree, (V, T), where V are the locations and T is the solution to the problem. (V, T) must be connected by definition, and we need to show that it does not contain a cycle. To prove that there are no cycles, we use a proof by contradiction. Assuming there is some edge in a proposed cycle, the tree without that edge is still connected as any path with that edge can now find a longer path around the rest of the cycle instead. This also in turn solves the problem and is less expensive, which gives us a contradiction. | + | We know that the minimum-cost solution to this problem can be turned into a tree, (V, T), where V are the locations and T is the solution to the problem. (V, T) must be connected by definition, and we need to show that it does not contain a cycle. To prove that there are no cycles, we use a proof by contradiction. Assuming there is some edge in a proposed cycle, the tree without that edge is still connected as any path with that edge can now find a longer path around the rest of the cycle instead. This also in turn solves the problem and is less expensive, which gives us a contradiction. A subset of the tree can be called a spanning tree of the graph. |
| + | There are three greedy algorithms which creates a minimum spanning tree. The first of with is Kruskal' | ||
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| + | It is considered " | ||
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| + | We can implement both Kruskal' | ||
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| + | Overall this section was difficult to follow for me. I had a difficult time understanding some of this during class, and the textbook readings did not help very much. Overall readability was about a 4 out of 10. | ||
| ===== 4.6: Implementing Kruskal' | ===== 4.6: Implementing Kruskal' | ||
| + | The Union-Find data-structure will store a representation of connected components that allows us to quickly and efficiently search and update these components. This turns out to be the same data structure in Kruskal' | ||
| + | To create this structure, we create an array Component, and a set with n elements. To create the union-find, we initialize the Component array to the set. We can optimize this set by choosing the name for the union to be the name of one of the sets. Furthermore, | ||
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| + | We can implement Kruskal' | ||
| ===== 4.7: Clustering ===== | ===== 4.7: Clustering ===== | ||
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| + | This section discusses clustering. Clustering can be used whenever one is attempting to organize a collection into various groups. There are various ways to group a collection. One way is by distance, such as with points on a plane. We can use minimum spanning trees to play a part in clusterings of maximum spacing. If we want to divide objects into k groups, we will have a k-clustering as a partition of a union into k nonempty sets. The spacing of a k-clustering is the minimum distance between any pair of points in different clusters. | ||
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| + | To find a clustering of maximum spacing, we want to cluster points as rapidly as possible. We grow a graph edge by edge, with connected components corresponding to clusters. This process will never create a cycle, but rather a union of trees. This procedure is extremely similar to Kruskal' | ||
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| + | ===== 4.8: Huffman Codes and Data Compression ===== | ||
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| + | This chapter discusses solving problems using data compression. Here, the problem is encoding symbols using bits. To convert various " | ||
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| + | One example of how data has been compressed is Morse code. Morse code translates each symbol into dots or dashes. However, Morse code removes ambiguity between letters that are represented similarly by adding a space in between each letter. If we were to turn this into bits, the ambiguity would remain as certain encodings are prefixes to others. A method must be built to eliminate the prefix problem. The method could work as follows: | ||
| + | Start reading bits from left to right, once you come across enough bits to match an encoding this becomes a letter, continue with the next bit and repeat. | ||
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| + | Now, we must account for letter frequencies to make the most optimal encoding. We can use a greedy algorithm to find the optimal prefix code. First, we can build a tree to help us build each encoding. We will create a binary tree where each time we go from a node to its left child we add a 0 and every time we go from a node to its right child we add a 1. By using a tree, we can see that the length of each symbol in bits is its corresponding layer in the tree. We want to fill the binary tree to make it optimal. | ||
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| + | The first thought of building is tree is to attempt to build it top down. However, if we knew the optimal prefix code, this would help a great amount. We could then simply fill in the nodes of the tree. We would start with the highest frequency letters and move down through the tree, labeling nodes in order of decreasing frequency. This is essentially the basis of Huffman' | ||
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| + | Huffman' | ||
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